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第二种,过C作CE⊥CD,交抛物线于E,过E作EF⊥y轴于F, 显然△OCD∽△FEC, 所以CF/EF=DO/CO=1/2, 所以EF=CF, 设E的横坐标为x,则CF=x/2, 因为E在抛物线上所以...
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